Résoudre ces équations : A = (x + 5)² + (x + 5)(x - 1) = 0 B = (x + 1)(5x - 1) - (x + 1)(3x - 12) = 0
Mathématiques
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Question
Résoudre ces équations :
A = (x + 5)² + (x + 5)(x - 1) = 0
B = (x + 1)(5x - 1) - (x + 1)(3x - 12) = 0
A = (x + 5)² + (x + 5)(x - 1) = 0
B = (x + 1)(5x - 1) - (x + 1)(3x - 12) = 0
2 Réponse
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1. Réponse winner123
bonjour
a = ( x+5) ( x +5) + ( x +5) ( x -1) = 0
a = ( x +5) ( x + 5 + x - 1) = 0
a = ( x + 5 ) ( 2 x + 4) = 0
soit x + 5 = 0 donc x = - 5
soit 2 x +4 = 0
2 x = - 4
x = - 2
B = ( x +1) ( 5 x - 1 - 3 x + 12) = 0
b = ( x +1) ( 2 x + 11) = 0
soit x +1 = 0 et x = - 1
soit 2 x + 11 = 0
2 x = - 11
x = - 11/2 -
2. Réponse nonotata
A = (x + 5)² + (x + 5)(x - 1) = 0
(x+5)(x+5+x-1) =0
(x+5)(2x+4) =0
x+5 = 0 2x+4 =0
x = -5 x =4/2 =2
B = (x + 1)(5x - 1) - (x + 1)(3x - 12) = 0(x+1)(5x-1-3x+12) =0
(x+1)(2x+11) =0
x+1 =0 2x+11 =0
x = -1 x = -11/2