Niveau maths 3 eme urgent en priorité les questions 1,2 et surtout 3 merci d'avance

(4x-17)²-64= 16x² -136x+289-64 = 16x²-136x +225

2/

(4x-17)²-64 =(4x-17)² -8² =(4x-17-8)(4x-17+8)=(4x-25)(4x-9)

3/

16x²-136x+225 =(4x-17)²-64=(4x-25)(4x-9)

donc

(4x-25)(4x-9) =0

4x-25 = 0                              4x-9 =0

4x = 25                                    4x =9

x =25/4                                       x = 9/4

donc solution ( 9/4 ; 25/4)